At the same time of day, a tree and a flagpole cast shadows as shown below.
1 answer:
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The initial value of the graph is where . Thus, in this case, the initial value is 12.
The rate of change of the graph is essentially the slope of the graph. In this case, we can use the slope formula:
and
are points on the graph
Let's use two points from the chart to find the slope:
In this case, the rate of change of the graph is 9.
Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions and
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction
shown in purple, then we can plot the second one
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
We want to find a linear equation that models the given situation.
The solution is p = $0.0001*q - $23
The general linear equation is:
p = m*q + c
Where m is the slope and c is the y-intercept.
If we know that the line passes through two points (x₁, y₁) and (x₂, y₂) then the slope can be written as:
Here we have the two points:
price = $9, boxes = 320,000
price = $8.50, boxes = 270,000
We can rewrite these as:
(320,000 , $9)
(270,000 , $8.50)
Then the slope of the line will be:
Then the line is something like:
p = $0.0001*q + c
To find the value of c we can use one of the two given points, I will use the first one, (320,000 , $9).
Replacing that in our equation we get:
$9 = $0.0001*320,000 + c
$9 - $0.0001*320,000 = c = -$23
Then the linear equation is:
p = $0.0001*q - $23
If you want to learn more you can read:
The solution to the question
