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stealth61 [152]
2 years ago
5

Each of the following sets of numbers represents dollars. Which set of numbers is most appropriate to label the six tick marks a

long the vertical axis (cost)?

Mathematics
1 answer:
Serggg [28]2 years ago
7 0

Answer:

D

Step-by-step explanation:

5 ounces is on the 3rd point up.

Each ounce costs $30, so 5 ounces costs $150. Divide it into 3.

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I need help ? I can’t figure it out can someone help me plz
dalvyx [7]

The answer is C).

If each cost .19 and ounce you would use x to indicate the unknown value therefore you will have .19x. the x is the amount of ounces which is 8. So .19 x 8 which equals 1.52.

8 0
3 years ago
What are the coordinates of the midpoint of segment whose endpoints are A(-2,7) and B(4,-2)?
FromTheMoon [43]
Around 10 of not a clue. Good luck on that!
3 0
1 year ago
I need help thank you
Alenkasestr [34]
Hello again! 
So just like in the last problem you would do the same here.
Solve for 3y + 6 = 3
Subtract 6 from both sides.
3y = -3
Divide by 3.
y = -1
Now plug it into 8y + 2.
8(-1) + 2 = ?
-8 + 2 = ?
= -6
I hope this helps love! :)
5 0
3 years ago
Find the equation of the sphere passing through pleft parenthesis negative 4 comma 7 comma 6 right parenthesis(−4, 7, 6) and qle
Oksi-84 [34.3K]

The equation of a sphere is:

(x – h)^2 + (y – k)^2 + (z – l)^2 = r^2

where h, k and l are the coordinates of the center of the sphere

 

Using the midpoint formula, the coordinate of the center is:

h = (-4 + 6) / 2 = 1

k = (7 + -5) / 2 = 1

l = (6 + 7) / 2 = 6.5

 

so the equation becomes:

(x – 1)^2 + (y – 1)^2 + (z - 6.5)^2 = r^2

 

we plug in any point, in this case point P to solve for r:

(-4 -1)^2 + (7 – 1)^2 + (6 - 6.5)^2 = r^2

r^2 = 61.25

 

So the full equation is:

<span>(x – 1)^2 + (y – 1)^2 + (z - 6.5)^2 = 61.25</span>

8 0
3 years ago
HELP! WILL GIVE BRAINLIEST! DO NOT TAKE ANSWERS OFF ONLINE, THEY ARE WRONG!!!! The following is an incomplete paragraph proving
ohaa [14]

Answer:

The correct option is B.

Step-by-step explanation:

Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .

Draw a diagonal AC.

In triangle BCA and DAC,

AC\cong ACAC≅AC (Reflexive Property of Equality)

\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)

\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)

The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.

By ASA postulate,

\triangle BCA\cong \triangle DAC△BCA≅△DAC

Therefore option B is correct

4 0
2 years ago
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