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lyudmila [28]
2 years ago
14

Which drawing shows two lines that intersect at Point a ax, tab, two lines ab, straight x a.​

Mathematics
1 answer:
leonid [27]2 years ago
5 0

The drawing which shows two lines that intersect at Point, A is as represented in Choice 1: Top-left corner.

Discussion:

In geometry, a line or straight line was introduced by ancient mathematicians to represent straight objects with negligible width and depth.

  • Lines are therefore an idealization of such objects, which are often described in terms of two points or referred to using a single letter.

Ultimately, The drawing which shows two lines that intersect at Point, A are as represented in Choice 1: Top-left corner.

Read more on intersection of lines:

brainly.com/question/9047265

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Please help with my math ​
Makovka662 [10]

first one is C and second is D

4 0
3 years ago
A regular convex polygon has eight sides. What is the measure of an exterior angle?
PSYCHO15rus [73]

Answer:

The measure of one exterior angle is 45 degrees.

Step-by-step explanation:

The formula to find exterior angle of and shape is 360 degrees divided by n (number of sides the shape has). 360 divided by 8 = 45 degrees.

4 0
3 years ago
Read 2 more answers
These cylinders are similar. Find the volume of
Basile [38]

Answer:

V_s=85\ cm^3

Step-by-step explanation:

Let V_s\ and\ V_b be the volumes of the smaller and bigger cylinder.

The formula for the volume of a cylinder is given by :

V=\pi r^2 h

As the two triangles are similar, the cube of their ratio would equal the ratio of their volume i.e.

\dfrac{V_s}{V_b}=(\dfrac{h_s}{h_b})^3\\\\\dfrac{V_s}{V_b}=(\dfrac{3}{5})^3\\\\\dfrac{V_s}{V_b}=0.216\\\\V_s=393\times 0.216\\\\V_s=84.8\\\\or\\\\V=85\ cm^3

So, the volume of the smaller cylinder is equal to 85\ cm^3.

3 0
3 years ago
A sine function is transformed such that it has a single x-intercept in the interval (0,pi), a period of pi and a y-intercept of
Alex787 [66]
Just to make sure we're using the same language, I'm going to use the function form of:

y = A\sin(kx) + h

[] I would agree that k = 2, since the period is only half as long as a normal sine function. So, we so far, have y = A sin(2x) + h. We still need to find A and h.

[] The y-intercept is 3. Remember that the y-intercept happens when x = 0. So, plugging in x = 0 into our formula, we have: 3 = A sin(2*0) + h. In other words, 3 = A sin(0) + h = 0 + h = h. So, we now know that h = 3. The formula is now y = A sin(2x) + 3.

[] Finally, there is a single x-intercept. Picture what the sine function looks like right now, it is floating in the air around y = 3. We need to stretch it vertically until it just grazes the x-axis. 

If A = 1, then our sine function bounces between 2 and 4 (+/- 1 around h = 3). But that doesn't touch 0, so no good.

If A = 2, then our sine function bounces between 1 and 5 (+/- 2 around h = 3). Again, not quite touching 0 yet.

The answer should be A = 3, then our sine function bounces between 0 and 6 (+/- 3 around h = 3).

The final formula is y = 3 sin(2x) + 3.
7 0
3 years ago
What is the value of this expression when a= - 3 and b=-2?<br> (3a^-2b^6/2a^-1b^5)^2
lisabon 2012 [21]

Answer:

so lets just rewrite it with A=-3 amd B=-2

(-9^4^-9^2^5)^2

which is equal to... 1!

Hope This Helps!!!

7 0
3 years ago
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