Let x represent the number.
.. x^2 +x = 2
.. x^2 +x +1/4 = 9/4 . . . . add 1/4 to complete the square
.. x +1/2 = ±3/2 . . . . . . . .square root
.. x = -2, 1
Numbers meeting that requirement are -2 and 1.
The sum of three even consecutive integers if the first integer is y will be 3y + 6.
First integer = y
Second integer = y + 2
Third integer = y + 4
Therefore, based on the expressions given above, the sum of the three integers will be:
= y + y +2 + y + 4
= 3y + 6
Therefore, the sum will be 3y + 6.
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Answer:
i canot help you
Step-by-step explanation:
this is a question that is collage level so i cannot help