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3 years ago

Help me with these questions plz

Mathematics

2 answers:

guajiro [1.7K]3 years ago

8 0

28 cm tall is your answer

Pepsi [2]3 years ago

6 0

28 cm tall.

hope it helps

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30 divided by (21-6)•4-27+82

damaskus [11]

Rounded 62 .1
But it goes on for a while but its 62.58...

7 0

3 years ago

If Kansas City is 108 miles away how many gallons of gas I needed to get there and then home

fenix001 [56]

Answer:

Well here's the issue...

Step-by-step explanation:

Since we have no idea what car you'll be using for the experiment, I can't tell you how many times you will have to fill er' up either. let's say you have a fuel efficient car like 27 mpg. that's highway and city combined. (34/25) And the trip is 216 miles round trip. And let's say you used 0 gallons while you were there. You would need to fill up exactly 8 times to get there and back. That's going off of 27 miles per gallon.

Hope this helps!!

6 0

3 years ago

URGENT! PLEASE HELP.

uysha [10]

Answer: a) BC = 1386.8 ft

b) CD = 565.8 ft

Step-by-step explanation:

Looking at the triangle,

AD = BD + 7600

BD = AD - 7600

Considering triangle BCD, we would apply the the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side. Therefore,

Tan 24 = CD/BD = CD/(AD - 700)

0.445 = CD/(AD - 700)

CD = 0.445(AD - 700)

CD = 0.445AD - 311.5 - - - - - - - -1

Considering triangle ADC,

Tan 16 = CD/AD

CD = ADtan16 = 0.287AD

Substituting CD = 0.287AD into equation 1, it becomes

CD = 0.445AD - 311.5

0.287AD = 0.445AD - 311.5

0.445AD - 0.287AD = 311.5

0.158AD = 311.5

AD = 311.5/0.158

AD = 1971.52

CD = 0.287AD = 0.287 × 1971.52

CD = 565.8 ft

To determine BC, we would apply the Sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse

Sin 24 = CD/BC

BC = CD/Sin24 = 565.8/0.408

BC = 1386.8 ft

4 0

3 years ago

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

7 0

3 years ago

The 11 foot long bed of a dump truck loaded with debris must rise an angle of degrees before the debris will spill out. Approxim

Ymorist [56]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. The complete question is:

The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.

Solution:

Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:

sin θ = opposite / hypotenuse

Using trigonometric identities, we can get that:

sin(30) = x / 12

This gives:

0.5 = x / 12

Cross multiplying the terms to get:

x = 12 * 0.5

x = 6 ft

Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.

4 0

3 years ago