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Masja [62]
2 years ago
11

Plzzz help meeee plzzzzz plzzzz

Mathematics
1 answer:
Rasek [7]2 years ago
3 0

Answer: A. 20%

Step-by-step explanation:

First, to find the total number of teachers, we can add 25+32+18+5+20=100

Next, we divide the number of teachers in 2014 (20) by the total number of teachers (100) as follows:

20 ÷ 100 = 0.2

Finally, to make 0.2 a percentage, we can multiply 0.2 X 100 = 20

Therefore, the correct answer is A.

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4gallons is how many cups of milk​
Vitek1552 [10]

Answer:


Step-by-step explanation:

4 gallons is 64 cups.

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3 years ago
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What does this expression respresent? 12f+24
iragen [17]
This means that it's 12 times f, then add that by 24. This f is a variable. It could be any number. First, try to find out what f equals. Then use that to find the answer.
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How do I simplify 5x+1??
bonufazy [111]
It is 5 because any thing times 1 is that number 

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Tell whether a triangle can have sides with the
Dmitry [639]

Answer:

3x+2 \ne x^2 \ne 2x for x = 4

Step-by-step explanation:

Given

Shape: Triangle

Dimension: 3x + 2, x^2 and 2x

x = 4

Required

Determine if it has equal sides

To do this, we simply substitute 4 for x in the given dimensions

<u>3x + 2</u>

3x + 2 = 3 * 4 + 2

3x + 2 = 12 + 2

3x + 2 = 14

<u>x^2 </u>

x^2 = 4^2

x^2 = 16

<u>2x</u>

<u></u>2x = 2 * 4<u></u>

2x = 8

3x+2 \ne x^2 \ne 2x for x = 4

8 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
3 years ago
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