All categories

2 years ago

Ain. 1.5 ft. 0.5 it. What is the surface area of the figure in square inches help

Mathematics

2 answers:

Fiesta28 [93]2 years ago

8 0

l=4in
b=0.5ft=6in
H=1.5ft=18in

$\\ \sf\Rrightarrow LSA=2(h)(l+b)$

$\\ \sf\Rrightarrow LSA=2(18)(6+4)$

$\\ \sf\Rrightarrow LSA=36(10)$

$\\ \sf\Rrightarrow LSA=360in^2$

Aleonysh [2.5K]2 years ago

3 0

Answer:

17.5 ft.²

Step-by-step explanation:

Surface area: 2(4 x 0.5) + 2(4 x 1.5) + 2(0.5 x 1.5)
=> 2(2) + 2(6) + 2(0.75)
=> 4 + 12 + 1.5
=> 17.5 ft.²

Conclusion:

Therefore, the surface area is 17.5 ft.².

Hoped this helped.

$GeniusUser$

You might be interested in

Fiona bought some socks that cost $4.95 for each pair and some belts that cost $6.55 each. Fiona spent $27.95 in all. Let a repr

Nookie1986 [14]

Answer:

4.95a + 6.55b = 27.95

3 0

3 years ago

Read 2 more answers

Find the volume of each prism. Please help mee and thank you.

inna [77]

Answer:

Step-by-step explanation:

4 0

2 years ago

Write a linear equation in slope intercept form to model a tree 4 feet tall the grows 3 inches per year

Hoochie [10]

Y = 3x + 48 where x is your number of years. I got 48 by multiplying 4 and 12 since there are 12 inches in a foot. (:

7 0

3 years ago

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

3 0

3 years ago

What is the slope of the line that contains the points (-2,2) and (3,4)

malfutka [58]

Answer: B. 2/5 *The answer must have a fraction.

Explanation:

Slope-intercept form: → $y=mx+b$

m: represents the slope and is constant.

b: represents the y-intercept.

Used rise/run.

$\frac{rise}{run}$

$x^1,y^1=(-2,2)$

$x^2,y^2=(3,4)$

You had to find the slope by using formula.

$Slope=\frac{y^2-y^1}{x^2-x^1}$

$\frac{4-2}{3-(-2)}$

subtract by the numbers and add the numbers too.

$\frac{4-2=2}{3-(-2)=3+2=5}$

$=\frac{2}{5}$

Hope this helps!

4 0

3 years ago