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3 years ago

HELPPPPPPPPP PLZZ

Mathematics

1 answer:

Over [174]3 years ago

6 0

we can start a relationship together

Step-by-step explanation:

im soo

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Y = 3x - 12x +9<br> In standard form?

xxMikexx [17]

Answer:

y=-9x+9

Step-by-step explanation:

There are only two like terms in the equation which I have underlined.

y= <u>3x - 12x</u> +9

To simplify it, you combine the like terms and get your equation in standard form.

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3 years ago

Compare the exponential functions f, g, and h which are shown below.

Nostrana [21]

Hello,
Please, see the detailed answer in the attached files.
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3 years ago

Find the x- and y-intercepts of the line with equation 8x - 4y = -64

maw [93]

Answer:

x-intercept:8

y-intercept:16

Step-by-step explanation:

This is the equation of a straight line. When the line crosses the x-axis that is the x- intercept, the corresponding y-coordinate will be zero. Substituting y = 0 into the equation and solving for x gives the x-intercept.

8x-(4×0)=-64

-8x=-64

x=8 <= the x-intercept.

Similarly, when the line crosses the y-axis the corresponding x- coordinate will be zero. Let x = 0 and solve for y.

(8×0)-4y=-64

-4y=-64

y=16 <= the y-intercept .

7 0

3 years ago

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Given the points a to zero 8, 0 what scale factor is applied to the create this change

Ganezh [65]

Answer:

Step-by-step explanation:

(2, 0) to (8, 0) is a 4/1 scale factor because 8/2 = 4

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3 years ago

At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

i.e. $22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

i.e. $22000=\frac{P\times 0.5265}{0.00625}$

i.e. $P=\frac{22000\times 0.00625}{0.5265}$

i.e. $P=\frac{137.5}{0.5265}$

i.e. $P=261.16$

Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0

3 years ago

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