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DiKsa [7]
3 years ago
8

Could you guys please help me with this

Mathematics
2 answers:
Anastasy [175]3 years ago
8 0
RRRRRRRRRRR I HATE THESE PROBLEMS


Alright...there are two faces with 7*12, giving us 2*84, next, two faces with 19*7, giving us 2*133, then one side with 19*12, then one side 15*19, then 2(9*12*1/2) then finally 9*19.  So.................  we have 1226.
Illusion [34]3 years ago
5 0
SA = 1,226 in.² (Hope this helps!)
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Five less than the product of a number and 3 is 14
lakkis [162]
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3 years ago
Find the coordinates of C' after a reflection across the line
iragen [17]
<h3>Answer:  (4,2)</h3>

==============================================================

Explanation:

C is at (0,0). Ignore the other points.

Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.

Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"

So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.

All of this is shown in the diagram below.

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