All categories

2 years ago

Please help it’s word problems, 30 points and brainliest if you give answers

Mathematics

1 answer:

pogonyaev2 years ago

8 0

Answer:

for 3c it's After Edgar's 9th quiz he would have a grade of 89%

Step-by-step explanation:

It is going up by 4 everytime so...

57,61,65,69,73,77,81,85,89

1. 2. 3. 4. 5. 6. 7. 8. 9.

(Sorry but it's hard to read)

You might be interested in

How to solve -16+x=-4 13

kotykmax [81]

Answer:

you want to isolate x so just add 16 to the right side (-4)

so -16 + x = -4

+16 +16

x=12

hope this helps :)

5 0

3 years ago

E Find the mode of the data set: 25,29, 22,19,20,29, 23, 29, 19,31

Vesna [10]

Answer:

the mode is 29

Step-by-step explanation:

the mode is the number that appears most often in a set of data, thus making it 29

7 0

2 years ago

Read 2 more answers

Help me plssss Espero que alguien me ayude

likoan [24]

(2/3) √26 --- 3. 40

3√5 --- 6. 71

1. 75π --- 5. 50

√111/2 --- 5. 27

those should be it

5 0

3 years ago

Solve the equation x/5 =9

Elena L [17]

Answer:

x = 45

Step-by-step explanation:

Given

$\frac{x}{5}$ = 9

Multiply both sides by 5

x = 5 × 9 = 45

7 0

3 years ago

Read 2 more answers

If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a

harkovskaia [24]

Given:

The function is:

$h(x)=x^2-3x+5$

To find:

The value of $h(2x+1)$ .

Solution:

We have,

$h(x)=x^2-3x+5$

Putting $x=2x+1$ , we get

$h(2x+1)=(2x+1)^2-3(2x+1)+5$

$h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5$

$h(2x+1)=4x^2+4x+1-6x-3+5$

On combining like terms, we get

$h(2x+1)=4x^2+(4x-6x)+(1-3+5)$

$h(2x+1)=4x^2-2x+3$

Therefore, the required function is $h(2x+1)=4x^2-2x+3$ .

3 0

3 years ago