9x8-29+30/15-15 I'm looking for the answer plz
1 answer:
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Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
Answer: In 2008 the population was 21,525,144
Step-by-step explanation:
You need to use the following formula for Exponential decay:
Where is the initial population in the year 0,
is the rate of decay and
is the time.
In this case, you can identify that:
Therefore, substituting these values into the formula for Exponential decay, you get:
Then, in 2008 the population was 21,525,144