Answer:
The value of rate of decrease of volume = - 3600 
Step-by-step explanation:
According to Boyle's law P V = C ------- (1)
Pressure ( P ) = 100 k pa = 10 
Volume ( V ) = 900 
Put these values in equation ( 1 ) we get,
⇒ C = 10 × 900 = 9000 N-cm = 90 N-m
Differentiate Equation ( 1 ) with respect to time we get,
⇒ V 
+ P 
= 0
⇒ V = - P
⇒ = - 
---------- (2)
This equation gives the rate of decrease of volume.
Given that Rate of increase of pressure = = 40
C = 90 N-m
P = 
pa = 10
V = 900
Put all the above values in equation 2 we get,
⇒ = - 
× 40
⇒ = - 3600
This is the value of rate of decrease of volume.
Answer:
6.02775720469
Step-by-step explanation:
step one: double check with calculator pls :)
step two pls <u><em>brainliest </em></u>
Answer:
7/15
Step-by-step explanation:
hope this helps?:)
-3 • (5x + 2y = 7)
-15x - 6y = -21
-2x + 6y = 9
__________
-17x = -12
x = 12/17
5(12/17) + 2y = 7
2y = 7 - 60/17
2y = 3.47
y = 1.735
The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
