Answer:
We want to find:
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D)
Here we can use Stirling's approximation, which says that for large values of n, we get:
Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D%20%3D%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7B%5Csqrt%7B2%2A%5Cpi%2An%7D%20%2A%28%5Cfrac%7Bn%7D%7Be%7D%20%29%5En%7D%20%7D%7Bn%7D%20%3D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Bn%7D%7Be%2An%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D)
Now we can just simplify this, so we get:
![\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B1%7D%7Be%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D%20%5C%5C)
And we can rewrite it as:
The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:
1.666666666666667%
3.00/1.80
1.666666666666667 as a fraction is 5/3
Answer:
A
Step-by-step explanation:
Let's check each one-by-one.
a.
we know 3.79 liters is 1 gallon, so 4 liters IS NOT LESS THAN 1 gallon
THis is false.
b.
We know 1 feet is 0.30 meters, so definitely 1 foot is less than 1 meter.
This is true.
c.
we know around 28.35 grams is 1 ounce, so definitely 25 grams is less than 1 ounce.
THis is true.
d.
We know 1 km is approximately 0.62 miles so 10 km would be around 0.62*10 = 6.2 miles
So definitely 9 miles IS GREATER than 10 km.
THis is true.
So answer choice A is false, only.
Step-by-step explanation:
since we are required to find side |BC| and the value of side |AB| is given as 6.3 cm
hence we find the cosine of the given angle...
cos71 = adjacent ÷ hypotenuse
cos71 = |AB| ÷ |BC|
cos 71 = 6.3 ÷ |BC|
|BC| = 6.3 ÷ 0.325
|BC| = 19.4 cm
