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8_murik_8 [283]
2 years ago
15

Solve by using the quadratic formula. (If there is no solution, enter NO SOLUTION.)

Mathematics
1 answer:
aleksandrvk [35]2 years ago
3 0

\dfrac 17 x^2 + 1 = \dfrac 37 x\\\\\implies x^2 +7 =3x~~~;[\text{Multiply both sides by 7}]\\\\\implies x^2 -3x +7 =0\\\\\text{Apply quadratic formula}~ x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}.\\\\\text{In  this case ,}~ a =1, b= -3 , c =7\\\\x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(7}}{2(1)}\\\\\implies x= \dfrac{3 \pm \sqrt{-19}}{2}\\\\\implies  x =\dfrac{ 3 \pm i\sqrt{19}}2\\\\\\\text{Smaller value of x } =\dfrac{ 3 -i\sqrt{19}}2\\\\\text{Larger value of x } =\dfrac{ 3 +i\sqrt{19}}2

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Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp
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If p(3-2i)=0, then complex number 3-2i is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated 3+2i is also a root of polynomial.

Then the polynomial will be of a form

p(x)=(x-(3-2i))(x-(3+2i))(x-a).

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