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2 years ago

Please help me! I'll give brainliest.

Mathematics

1 answer:

pochemuha2 years ago

3 0

Answer:

2.166666666666667

Step-by-step explanation:

0 + 1 + 1 + 3 + 4 + 4 = 13

13 divided by 6 = 2.166666666666667

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Mr.Rivas bought a can of paint. He used 3/8 of it to paint a bookshelf.He used 1/4 of it to paint a wagon. He used some of it to

Galina-37 [17]

Mr.Rivas used 2/8 of paint for the birdhouse

8 0

3 years ago

suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in

Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = $\frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}$ credit hours * gpa

in our case, it would be:

CGPA = $\frac{(2.75*105)+(4*15}{105+15}$

=> $\frac{(288.75)+(60)}{120}$

=> $\frac{348.75}{120}$

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0

3 years ago

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$