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Stels [109]
2 years ago
15

Pls somebody solve this I still don’t understand it yet :/ please

Mathematics
2 answers:
Fofino [41]2 years ago
8 0

Answer:

first blank 39, second 9/39 i think, and third 351

Step-by-step explanation:

i haven't done something like this in a long time so i dont know if its completely correct or correct at all

vovangra [49]2 years ago
7 0

Check the picture below.

the assumption being that the y-axis represents the water level more or less and the x-axis represents the minutes elapsed, we're also assuming this rate is constant, so it creates a straight-line on the cartesian plane.

We know that every 3 minutes pass, the level rises by 13 cm, let me reword that, we know that as the "rise" is 13, the "run" is 3, well, slope is rise/run, that simply gives us a slope of 13/3.

Now, we have another point on the line, (9 , y), whatever "y" might be, we know that the slope is y/x or rise/run, so we can say that

\stackrel{\textit{given slope}}{\cfrac{13}{3}}=\stackrel{\textit{equivalent slope}}{\cfrac{y}{9}}\implies 117=3y\implies \cfrac{117}{3}=y\implies 39=y

we know the slope is 13/3 or namely 13 cm every 3 mins, what about for just 1 minute? we can simply get their quotient, 13 ÷ 3 which is about 4.3 cms/min.

You might be interested in
Create a vector named iq of 100 elements of N(100,20) (normal with a mean of 100 and std dev of 20) data. 6. add 10 to every ele
DaniilM [7]

Answer:

See code and explanation below.

Step-by-step explanation:

For this case we can use the following R code to create a vector of 100 elements from a normal distribution given by:

X \sim N (\mu = 100. \sigma= 20)

The function rnorm creates a sample data from the normla distribution with the mean and deviation provided

> normal<-rnorm(100,mean = 100,sd=20)

We can visualize the data like this

> normal

 [1]  87.47092 103.67287  83.28743 131.90562 106.59016  83.59063 109.74858 114.76649 111.51563

[10]  93.89223 130.23562 107.79686  87.57519  55.70600 122.49862  99.10133  99.67619 118.87672

[19] 116.42442 111.87803 118.37955 115.64273 101.49130  60.21297 112.39651  98.87743  96.88409

[28]  70.58495  90.43700 108.35883 127.17359  97.94425 107.75343  98.92390  72.45881  91.70011

[37]  92.11420  98.81373 122.00051 115.26351  96.70953  94.93277 113.93927 111.13326  86.22489

[46]  85.85010 107.29164 115.37066  97.75308 117.62215 107.96212  87.75947 106.82239  77.41274

[55] 128.66047 139.60800  92.65557  79.11731 111.39439  97.29891 148.03236  99.21520 113.79479

[64] 100.56004  85.13454 103.77585  63.90083 129.31110 103.06507 143.45223 109.51019  85.80107

[73] 112.21453  81.31805  74.92733 105.82892  91.13416 100.02211 101.48683  88.20958  88.62663

[82]  97.29643 123.56174  69.52866 111.87892 106.65901 121.26200  93.91632 107.40038 105.34198

[91]  89.14960 124.15736 123.20805 114.00427 131.73667 111.16973  74.46816  88.53469  75.50775

[100]  90.53199

Then we can add 10 to each element of the vector like this:

> normal1<-normal+10

And we can visualize the results like this

> normal1

 [1]  97.47092 113.67287  93.28743 141.90562 116.59016  93.59063 119.74858 124.76649 121.51563

[10] 103.89223 140.23562 117.79686  97.57519  65.70600 132.49862 109.10133 109.67619 128.87672

[19] 126.42442 121.87803 128.37955 125.64273 111.49130  70.21297 122.39651 108.87743 106.88409

[28]  80.58495 100.43700 118.35883 137.17359 107.94425 117.75343 108.92390  82.45881 101.70011

[37] 102.11420 108.81373 132.00051 125.26351 106.70953 104.93277 123.93927 121.13326  96.22489

[46]  95.85010 117.29164 125.37066 107.75308 127.62215 117.96212  97.75947 116.82239  87.41274

[55] 138.66047 149.60800 102.65557  89.11731 121.39439 107.29891 158.03236 109.21520 123.79479

[64] 110.56004  95.13454 113.77585  73.90083 139.31110 113.06507 153.45223 119.51019  95.80107

[73] 122.21453  91.31805  84.92733 115.82892 101.13416 110.02211 111.48683  98.20958  98.62663

[82] 107.29643 133.56174  79.52866 121.87892 116.65901 131.26200 103.91632 117.40038 115.34198

[91]  99.14960 134.15736 133.20805 124.00427 141.73667 121.16973  84.46816  98.53469  85.50775

[100] 100.53199

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

If we want to calculate the mean and standard deviation for the original data we can do this:

> mean(normal)

[1] 102.1777

And the standard deviation with:

> sd(normal)

[1] 17.96399

Other way to calculate the deviation is:

> sqrt(sum((normal-mean(normal))^2/(length(normal)-1)))

[1] 17.96399

7 0
3 years ago
In 2010, the population of Houston, Texas, was 2,099,451 and the population density was 3,501 people per square mile. What was H
weeeeeb [17]
In 2010 the land area was: 

2099451 persons / 3501 persons/m^2 = 599.7=600

The land area in 2010 was around 600 square miles. 
7 0
3 years ago
Read 2 more answers
There are 219 people at the science camp. 112 people are enrolled in the chemistry class, and 45 people are enrolled in the phys
eimsori [14]

Answer:

The correct answer is - 17.

Step-by-step explanation:

Given:

total students = 219

in chemistry = 112

in physics = 45

not enrolled in either of these = 79

solution:

The number of students in both classes can be calculated by

P ( A or B) = P (A) + P (B) - P (A and B)

then putting and solving the given vaues in formula

=> (219-79) = 112+45-x

=> 140 = 157 -x

=> 17 = x

6 0
3 years ago
A polling company is trying to estimate the percentage of adults that consider themselves happy. A confidence interval based on
Digiron [165]

Answer:

They should interview 1620 adults now.

Step-by-step explanation:

Margin of error of a confidence interval:

The margin of error of a confidence interval has the following format:

M = z\frac{\sigma}{\sqrt{n}}

In which z is related to the confidence level, \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

z wont change, neither will \sigma

We want to increase n as such the margin of error is reduced to one third.

We have that the margin of error is inversely proportional to the square root of the size of the sample, which means that for the margin of error to be reduced to one third, the sample size has to be multiplied by 3^2 = 9. So

180*9 = 1620

They should interview 1620 adults now.

6 0
3 years ago
Please help!!!!!!!! ​
xxMikexx [17]

Answer:

1) 0.50

2) 1

using probability formula

6 0
3 years ago
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