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Harlamova29_29 [7]
2 years ago
15

How much did jennie earn if she got $40 for babysitting plus a 15% tip

Mathematics
1 answer:
vazorg [7]2 years ago
7 0

Answer:

$46

Step-by-step explanation:

100% of 40 is 40. 10 percent of 40 is 4. 5% of 40 is 2. 40+4+2=46.

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What is 55x+6=120<br><br> (Fraction form)
mezya [45]

Step-by-step explanation:

55x+6=120

55x=120-6

55x=114

X=114/55

8 0
3 years ago
PLEASE HELP WITH THIS MATH
s2008m [1.1K]
-5 because u subtract them both and they equal it ha
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3 years ago
What is the area of this figure. <br><br><br> 128 in<br> 136 in<br> 153 in<br> 258 in
aliya0001 [1]
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
6 0
3 years ago
Find the average of 8.4 7.5 12.9 and 10.6 also the method how to do it​
SashulF [63]
Find the average :8.4+7.5+12.9+10.6 divided by four
8 0
3 years ago
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0
3 years ago
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