Answer:
7/25 is correct answer dude
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Converted to standard form</u>
- 8*10^-7 = 8*0.0000001 = 0.0000008
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
-4m + 4
Step-by-step explanation:
you distribute the -4 to the m making -4m and then distribute -4 to the -1 which makes +4
