Answer:
y = -3/8(x + 2)^2 + 8
Step-by-step explanation:
vertex form is
y = a(x - b)^2 + c where a is a constant and (b,c) is the vertex.
The maximum is at (-2, 8) because x 8 = height and x =-2 is equn. of symmetry
So here we have
y = a(x - (-2))^2 + 8
y = a(x + 2)^2 + 8
Now at the point (-6, 2):
2 = a(-6+2)^2 + 8
2 = 16a + 8
16a = -6
1 = -3/8.
So our equation is y = 3/8(x + 2)^2 + 8
Answer:
? ≈ 6.5 yd
Step-by-step explanation:
the area (A) of a triangle is calculated as
A =
bh ( b is the base and h the perpendicular height )
here A = 13.3 and h = 4.1 , then
× 4.1b = 13.3 ( multiply both sides by 2 to clear the fraction )
4.1b = 26.6 ( divide both sides by 4.1 )
b = ? ≈ 6.5 yd ( to the nearest tenth )
Answer:
Coefficient
Step-by-step explanation:
If it is 10a^3 (10 times the variable "a" cubed), then 10 is the coefficient.
Answer:
y = - 6x - 2
Step-by-step explanation:
The straight line equation is y = mx + c
First step is to bring the equation given to this form, where you make y the subject.
Now you can easily note down the gradient(m1). You will need it to find the gradient(m2) of the perpendicular line, because m1 × m2 = -1
After you have that substitute the value and the values of x and y given to find c .
Lastly, substitute the value of m2 and c into y = mx + c to find the line that is perpendicular .
Hope I was able to help:)))