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3 years ago

Find the missing lengths of the sides.

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer: 3 and 3Sq(3)
(WORK SHOWN BELOW)

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Can someone please help me with this

alina1380 [7]

Answer:

Step-by-step explanation:

x + 1 < 2

x + 1 - 1 < 2 - 1 do the math by subtracting one from both sides

x < 1

3 0

3 years ago

Add <br> (x - 10) + (3x + 6)

Ipatiy [6.2K]

Answer:

your answer is 4x-4

your welcomeee

7 0

2 years ago

Adrian

Goshia [24]

Answer:

Hence, both Marlon and Adrian both have the same at bats percentage.

Step-by-step explanation:

Marlon's at bats :

Number of at bats = 15

Hits = 6

Hit percentage = 6/15 * 100% = 40%

Adrian :

Number of at bats = 10

Hits = 4

Hit percentage = 4/10 * 100% = 40%

Hence, both Marlon and Adrian both have the same at bats percentage.

5 0

3 years ago

g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh

Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=10$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10$

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

$When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute$