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3 years ago

Help me with the whole thing pls

Mathematics

1 answer:

Maksim231197 [3]3 years ago

5 0

Answer:

B and 90%

Step-by-step explanation:

4500 = m•5000

m = 0.9 × 100%

90% of the books are fiction

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A number greater than -5

Serggg [28]

Answer:

Hi there!

Your answers are:

1) x> 5

Some numbers that would fit this equation are 6, 7, 8, etc!

2) x<= 30

Some numbers that would fit this are 30, 29, 28, etc!

3) x>= 17

Some numbers that would fit this equation are 17, 18, 19, etc!

4) x>= 90

Some numbers that would fit this are 90, 91, 92, etc!

Hope this helps!

5 0

3 years ago

A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe

soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 87, thus $\mu = 87$ .
The standard deviation is of 25, thus $\sigma = 25$ .

Item a:

This probability is 1 subtracted by the p-value of Z when X = 60, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 87}{25}$

$Z = -1.08$

$Z = -1.08$ has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the p-value of Z when X = 110, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 87}{25}$

$Z = 0.92$

$Z = 0.92$ has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the p-value of Z when X = 110 subtracted by the p-value of Z when X = 60.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is 1 subtracted by the p-value of Z when X = 125, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 87}{25}$

$Z = 1.52$

$Z = 1.52$ has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0

3 years ago

7(x + 4) + 5(x-6) please expand and simplify

Neporo4naja [7]

Answer:

12x − 2

Step-by-step explanation:

7(x+4)+5(x−6)

Distribute:

=(7)(x) + (7)(4) + (5)(x) + (5)(−6)

=7x + 28 + 5x − 30

Combine Like Terms:

=7x + 28 + 5x − 30

=(7x+5x) + (28−30)

= 12x − 2

8 0

3 years ago

Read 2 more answers

2 x <img src="https://tex.z-dn.net/?f=%5Csqrt%7B36%7D" id="TexFormula1" title="\sqrt{36}" alt="\sqrt{36}" align="absmiddle" clas

Andrei [34K]

The answer is 48
2x6+36
12+36=48

4 0

3 years ago

Read 2 more answers

A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Fin

Debora [2.8K]

Answer:

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}$

The margin of error of this interval is:

$MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}$

The critical value of z for 94% confidence level is, z = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

$MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}$

$=1.88\times\frac{3}{\sqrt{84}}\\\\=0.6154$

Thus, the margin of error for the 94% confidence interval is 0.6154.

7 0

3 years ago