First solve for one variable
solve for a in second eqatn
minus 3x both sides
a=17-3x
sub 17-3x for a in first equaiton
2(17-3x)+2x=18
34-6x+2x=18
34-4x=18
minus 34 both sides
-4x=-16
divide both sides by -4
x=4
sub back
a=17-3x
a=17-3(4)
a=17-12
a=5
a is 5
x=4
WORK SECTION (without thoughts)
2a+2x=18 to a+x=9
a+3x=17
a=17-3x
(17-3x)+x=9
17-2x=9
-2x=-8
x=4
a=17-3(4)
a=17-12
a=5
x=4
a=5
Answer: Well its not GREAT context but it should be 8 divided by 1/2=s
Step-by-step explanation:
Georgia will need 5 containers
∠ABX is an inscribed angle.
The measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc AX = 2*∠ABX = 2 * 64 = 128°
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the <span>intercepted arcs </span>⇒
∠ACB = (arc AB - arc AX)/2 = (152 - 128)/2 = 24/2 = 12°
