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2 years ago

14. Which statement about the aquaculture industry in the US is true?

1 answer:

4 0

Americans are known to import more than 85 percent of all the seafood they eat. The true statement about the aquaculture industry in the US is Interest in aquaculture has been increasing.

A lot of keen interest is been shown in the aquaculture sector in the US. A poll carried out in the US has show that there has been growing interest in aquaculture in US federal waters.

This interest was due to different factors such as;

Technological advances
The changes in the attitudes of the environmental community etc.

Learn more about Aquaculture from

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During which change of state would the volume of a substance increase the most?

mote1985 [20]

Answer:

Gas/vaporization

Explanation:

The most stare has the high volume is the gas state. So the answer is between vaporization and sublimation

8 0

3 years ago

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he Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In th

Vika [28.1K]

Answer:

148.2 g of H20

Explanation:

Equation of reaction: 4NH3 + 5O2 ---> 4NO + 6H20

From the equation above, 4 moles of ammonia reacts with 5 moles of oxygen gas to produce 6 moles water.

Molar mass of NH3 = 17 g/mol;

Molar mass of O2= 32 g/mol;

Molar mass of H2O = 18 g/mol

First, we determine the limiting reactant:

4*17 g of NH3 reacts with 5*32 g of O2

Mass Ratio = 68 : 160

Therefore, NH3 is the limiting reactant.

68 g of NH3 reacts to produce 6* 18 g of H20 = 108 g of H2O

93.3 g of NH3 will react to produce (93.3 * 108)/68 g of H20 = 148.2 g of H2O

Therefore, the maximum amount of H2O produced = 148.2 g

7 0

3 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.51 kJ/mol at 25 °C.

SVEN [57.7K]

Answer:

(a) [A] = 0.13 M, [B]= 0.23 M and [C] = 0.17 M.

(b) Option B.

Explanation:

The reaction given:

A(aq) + B(aq) ⇄ C(aq) (1)

Initial: 0.30M 0.40M 0M (2)

Equilibrium: 0.3 - x 0.4 - x x (3)

The equation of Gibbs free energy of the reaction (1) is the following:

$\Delta G^{\circ} = - RTLn(K_{eq})$ (4)

where ΔG°: is the Gibbs free energy change at standard conditions, R: is the gas constant, T: is the temperature and $K_{eq}$ : is the equilibrium constant

(a) To calculate the concentrations of A, B, and C at equilibrium, we need first determinate the equilibrium constant using equation (4), with ΔG°=-4.51x10³J/mol, T=25 + 273 = 298 K, R=8.314 J/K.mol:

$K_{eq} = e^{-\frac{\Delta G^{\circ}}{RT}} = e^{-\frac{-4.51\cdot 10^{3} J/mol}{8.314 J/K.mol \cdot 298 K}} = 6.17$ (5)

Now, we can calculate the concentrations of A, B, and C at equilibrium using the equilibrium constant calculated (5):

$K_{eq} = \frac{[C]}{[A][B]} = \frac{x}{(0.3 - x)(0.4 - x)}$ (6)

Solving equation (6) for x, we have two solutions x₁=0.69 and x₂=0.17, and by introducing the solution x₂ into equation (3) we can get the concentrations of A, B, and C at equilibrium:

$[A] = 0.3 - x_{2} = 0.3 - 0.17 = 0.13 M$

$[B] = 0.4 - x_{2} = 0.4 - 0.17 = 0.23 M$

$[C] = x = 0.17 M$

Notice that the solution x₁=0.69 would have given negative values of the A and B concentrations.

(b) If the reaction had a standard free-energy change of +4.51x10³J/mol, the equilibrium constant would be:

$K_{eq} = e^{-\frac{\Delta G^{\circ}}{RT}} = e^{-\frac{4.51\cdot 10^{3} J/mol}{8.314 J/K.mol \cdot 298 K}} = 0.16$

By solving the equation (6) for x, with the equilibrium constant calculated, we can get again two solutions x₁ = 6.9 and x₂= 0.017, and by introducing the solution x₂ into equation (3) we can get the concentrations of A, B, and C at equilibrium:

$[A] = 0.3 - x_{2} = 0.3 - 0.017 = 0.28 M$

$[B] = 0.4 - x_{2} = 0.4 - 0.017 = 0.38 M$

$[C] = x = 0.017 M$

Again, the solution x₁=6.9 would have given negative values of the A and B concentrations.

Hence, the correct answer is option B: there would be more A and B but less C.

I hope it helps you!

7 0

3 years ago

All elements in the same group A) have similar chemical properties. B) are not similar in any way. C) are in the same state at r

leva [86]

Answer:

Have similar chemical properties

Explanation:

The periodic table of elements is made up of groups or families and periods.
Elements in the same group or chemical family share similar chemical properties.
For example, elements in group II have similar chemical properties. They include Calcium and magnesium.
A similar chemical property of group II elements is that they react with water to form metal hydroxide and hydrogen gas.

4 0

4 years ago

Read 2 more answers

The melting point of sugar is 186°C. At room temperature, in which state is sugar found

Viktor [21]

Answer:

solid

Explanation:Sucrose is a solid at STP, which stands for standard temperature and pressure.

8 0

3 years ago