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timurjin [86]
3 years ago
12

SEP Develop Models Each helium atom has two protons. Sketch models

Chemistry
1 answer:
RSB [31]3 years ago
6 0

Protons and neutrons are located in the nucleus of the atom while the electrons move in the trajectory of the shell

<h3>Further explanation   </h3>

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.  

So Isotopes are elements that have the same Atomic Number (Proton)  

Isotopes of Helium : helium-3 and helium-4

  • ₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

  • ₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

  • ₂⁴He

protons = 2

electrons=protons=2

neutron=mass number-atomic number=4-2=2

Protons and neutron in the nucleus, electrons in the shell

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Consider the reaction where barium sulfate can be prepared from 2.76 mol of sodium sulfate and excess barium acetate. Sodium ace
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Answer:

1. Na2SO4(aq)+C4H6BaO4(aq) --> BaSO4(s) + 2C2H3NaO2(aq)

2. 2Na^+1(aq) + SO4^-2(aq) + 4C^+4(aq) + 6H^+1(aq) + Ba^-2(aq) + 4O^-2(aq) --> BaSO4(s) + 2C^-4(aq) + 2H^+1(aq) + 3Na^+1(aq) + 2O^-2(aq)

3. Ba^+2(aq) + SO4^-2(aq) --> BaSO4(s)

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What occurs in solvation
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How do tidal bulges form?
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2 years ago
How many grams of H2O are produced when 5.38g of O2 is reacted?
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An unknown compound containing only C and H was burnt, yielding 10.2 g of CO2 and 6.3 g of H2O. With a molecular weight of about
Lisa [10]

Answer:

C_2H_6

Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

m_C=10.2gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1mol C}{1molCO_2}=0.232 molC

Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

m_H=6.3gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH_2}{1molH_2O}  =0.7molH

Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:

C:\frac{0.232}{0.232}=1\\ \\H:\frac{0.7}{0.232}=3

Whose molar mass is:

M_{CH_3}=12+1*3=15g/mol

Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

C_2H_6

Which is actually ethane.

Regards.

3 0
3 years ago
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