Write 125 as a power using the number five as the base I’m looking for the answer

Name the figure below in two different ways.

12345 [234]

Answer:

LDM

MDL

Step-by-step explanation:

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3 years ago

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. Al's Omelets Al's House of Eggs N'at makes omelets. Al begins each day with 150 eggs to make his famous Bestern Western Omelet

Dvinal [7]

At the beggin there are 150 eggs, after making 1 omeltet, there are 144 eggs, after the second omelet, there are 138 eggs, etc.

By the given statement you can notice that each omelet demands 6 eggs. Then, after making each omeltet Al has 6 eggs lower. This can wrtten numerically as follow:

150, 144, 138, 132, 126, 120,...

That is equivalent to:

150-6, 150-6-6, 150-6-6-6, 150-6-6-6-6, 126-6-6-6-6-6, ... , 150 - 6n

where n is the nth omelet made by counting from the begining of the day.

8 0

1 year ago

A triangle has vertices at L(2, 2), M(4,4), and N(1,6). The

pav-90 [236]

Answer:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6)

Step-by-step explanation:

90 degree rotation from (x,y) results in (-x, y) and 180 degree results in (-x,-y)

The coordinates will change accordingly

L(2,2) will become L'(-2,-2)

M(4,4) will become M'(-4,-4)

and

N(1,6) will become N'(-1,-6)

So the correct statements are:

The rule for the transformation is (x, y) + (-X, -Y)

The coordinates of L'are (-2,-2).

The coordinates of N' are (-1,-6) ..

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3 years ago

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What is x>8,x<0 written in interval notation?

vazorg [7]

Answer:

(-∞, 0) U (8, ∞)

Step-by-step explanation:

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3 years ago

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Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago