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frosja888 [35]
2 years ago
8

Write 125 as a power using the number five as the base I’m looking for the answer

Mathematics
2 answers:
maksim [4K]2 years ago
5 0

Answer:

5³

Step-by-step explanation:

5*5*5=125

VMariaS [17]2 years ago
4 0
5^3
5 times 5 times 5 = 125
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Solve the equation 7j=11 <br> Enter each line of working as an equation.
NeTakaya

Answer:

j=1.571

Step-by-step explanation:

to get j by itself you have to divide 7 by 11

so,

11/7=j

j=1.571

7 0
3 years ago
What is the area of the rectangle with the given dimensions? *
exis [7]

Given:

The dimensions of a rectangle are 2x-5 and 3x+3.

To find:

The expression that represents the area of the rectangle in simplest terms.

Solution:

Area of a rectangle is:

Area=Length\times Width

The dimensions of a rectangle are 2x-5 and 3x+3. So, the area of the given rectangle is:

Area=(2x-5)\times (3x+3)

Area=2x(3x)+2x(3)-5(3x)-5(3)

Area=6x^2+6x-15x-15

Area=6x^2-9x-15

Therefore, the correct option is F, i.e., 6x^2-9x-15.

4 0
3 years ago
What is the value of x? Enter your answer in the box.<br><br><br><br> i need to post graph
kondaur [170]
2x + 2 = 3x - 52
x = 54
4 0
3 years ago
I NEED HELP FAST what is y+1=5/6(x-2) in standard form?
Irina18 [472]

Answer:

\large\boxed{5x-6y=16}

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in the point-slope form. Convert:

y+1=\dfrac{5}{6}(x-2)\qquad\text{multiply both sides by 6}\\\\6y+6=6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}(x-2)\\\\6y+6=5(x-2)\qquad\text{use the distributive property}\\\\6y+6=(5)(x)+(5)(-2)\\\\6y+6=5x-10\qquad\text{subtract 6 from both sides}\\\\6y+6-6=5x-10-6\\\\6y=5x-16\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+6y=5x-5x-16\\\\-5x+6y=-16\qquad\text{change the signs}\\\\\boxed{5x-6y=16}

6 0
3 years ago
Solve by factoring:<br>4x² - 8x=0​
AnnyKZ [126]

Answer:

Step-by-step explanation:

4x² - 8x= 0​

4x(x -2) = 0

: 4x = 0 or x - 2 = 0

4x = 0

Dividing by 4

x = 0/4

x = 0

And

x - 2 = 0

x = 2

5 0
3 years ago
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