Kinetic engery = -1/2mv^2
Work = Fd
Combine:
-1/2mv^2 - Fd = 0
-1/2mv^2 = (0.30*15000*9.81*cos(6))d = 0
Multiply both sides by 2:
v^2 = 2d(0.30*9.81*cos(6))
Solve for d:
d=v^2 / 2(0.30*9.81*cos96))
v = speed:
d = 35^2 / 2*0.30 * 9.81 * cos(6)
d = 1225 / 5.85376
d = 209.27 meters. Round answer as needed.
Answer:
<u>A. Mean = 402.5</u>
<u>B. Variance = 77,556.25</u>
<u>C. Standard Deviation = 278.49</u>
Step-by-step explanation:
Let's calculate the mean, variance and standard deviation of the set of numbers given:
A. Mean = (45 + 340 + 400 + 825)/4 = 1,610/4 =<u> 402.5</u>
B. Variance [(45 - 402.5)² + (340 - 402.5)² + (400 - 402.5)² + (825 - 402.5)²]/4 = [(127,806.25 + 3,906.25 +6.25 + 178,506.25/4 =<u> </u><u>77,556.25</u>
C. Standard Deviation = √Variance = √77,556.25 =<u> 278.49</u>
Answer:
1= 0.5
2= 5 dollors
Step-by-step explanation:
Volume = W*L*H
30 = 5*L*H old one
Volume = 2*5*L*H new one
Volume new one = 2*5*L*H =2*(5*L*H)=2*30=60
Answer is C
Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.
Multiply by 2 on both sides.
Substitute m∠NRQ = 60°.
The measure of minor arc NQ is 120°.
