Hi,
Let assume a the west side,
b the length of the north wall (i suppose the answer is smaller then the barn.
Cost of the fence= a*6+a*12+b*12=3000 $.
So 3a+2b=500==>b=(500-3a)/2
Area =a*b=a(500-3a)/2= 250a-3/2a²
Derivate the area ==> 250-3a=0
==> a=250/3 and b=(500-3*250/3)/2=125
Width=125 (feet)
Length=250/3=83.333 (feet)
Answer:
b = 8
c = 16
Step-by-step explanation:
From the given right triangle,
a = 
, m(∠B) = 30°
By applying sine rule in the given triangle,
cos(B) = 
cos(B) = 
cos(30°) = 
c = 16
Further we apply tangent rule,
tan(B) = 
tan(30°) = 
b = 8
Answer:
1486.67 or 1487.
Step-by-step explanation:
Find the average of those three things. Add 2,340 plus 470 plus 1650. You get 4460. Since you have three costs, divided 4460 by 3, which is 1486.6 repeating. Round to the nearest hundredth which is 1486.67. Hope this helps!
Urface area = area of the square + area of the 4 triangles
= 6*6 + 4(1/2*6*6)
= 36 + 4 * 18 = 108 sq cms
