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2 years ago

I need the answer one question one but if u have question 2 it's fine

SAT

1 answer:

olga_2 [115]2 years ago

5 0

Answer:

1.) 24

2.) 22.5

Explanation:

area of triangle =1/2×b×h

1.) b=8

h=6

a=1/2×6×8

a=24

ANSWER: D.) 24

2.). b=9

h=5

a=1/2×9×5

a=22.5

ANSWER: D.) 22.5

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Naddik [55]

Given what we know, we can confirm that the next step to take is to give ventilations to assist the patient in breathing until EMS arrives.

<h3>What are ventilations?</h3>

Ventilation is a form of assisted breathing. This is often done through the use of machines but can be achieved through manual means as well when necessary, such as in this situation. The lifeguard will give ventilation once every 5 or so seconds to bring the patient's breathing rate to a steady 12 times per minute until EMS arrives.

Therefore, we can confirm that the next step to take is to give ventilations at a rate of 12 times per minute to assist the patient in breathing steadily until EMS arrives.

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2 years ago

In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exa

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Using the binomial distribution, it is found that there is a 0.6836 = 68.36% probability that she guesses at least one right.

For each question, there are only two possible outcomes, either she gets it right or she does not get it right. The probability of getting a question right is independent of any other question, hence the <em>binomial distribution</em> is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 5 questions, hence n = 5.

For each question, she guesses one out of 4 options, hence p = 1/4 = 0.25.

The probability that she guesses at least one right is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.25)^{0}.(0.75)^{4} = 0.3164$

Hence:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3164 = 0.6836$

0.6836 = 68.36% probability that she guesses at least one right.

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2 years ago

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zhenek [66]

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3 years ago

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