If you are given the graph of h (x) = log subscript 6 baseline x, how could you graph m (x) = log subscript 6 baseline (x + 3)?

Question

1 year ago

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If you are given the graph of h (x) = log subscript 6 baseline x, how could you graph m (x) = log subscript 6 baseline (x + 3)?

translate each point of the graph of h(x) 3 units up. Translate each point of the graph of h(x) 3 units down. Translate each point of the graph of h(x) 3 units right. Translate each point of the graph of h(x) 3 units left

SAT

2 answers:

Ilia_Sergeevich [38] · Answer 1 · 2023-01-18T00:05:06+03:00

Ilia_Sergeevich [38]1 year ago

8 0

Answer:

D on edge

Explanation:

i saw the answer on another site

4vir4ik [10] · Answer 2 · 2023-01-17T22:07:49+03:00

The method of graphing m(x) = log₆(x + 3) is; by translating each point of the graph of the function h(x) 3 units to the left.

<h3>How to Translate Functions?</h3>

The function we are given is; h(x) = log₆x

From the given function, we notice that the function m(x) is the function h(x). However, it is shifted 3 units to the left.

Thus, it means that we could graph the function m(x) by translating each point of the graph of the function h(x) 3 units to the left.

Thus, the conclusion of this method of graphing m(x) = log₆(x + 3) is by translating each point of the graph of the function h(x) 3 units to the left.

Read more about Function Translations at; brainly.com/question/26238840