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Thepotemich [5.8K]
3 years ago
15

Which of the binomials below is a factor of this trinomial? x^2-7x-44

Mathematics
2 answers:
Nostrana [21]3 years ago
7 0

Answer:

C. (x -11)

Step-by-step explanation:

The given trinomial is x^2 - 7x - 44

Let's factor it. To find factor, we need to find the factors of -44 such that when you add them, we have to get -7

-44 = -11*4

- 7 = -11 + 4

so the correct factors are -11 and 4

Now we can write the middle term - 7x = -11x + 4x

x^2 - 7x - 44 = x^2 - 11x + 4x - 44

Now let's group the first two terms and second two terms and factor it.

= x(x - 11) + 4(x - 11)

Here (x-11) is common factor, so we can take outside and rewrite.

= (x - 11)(x + 4)

So the factors are (x - 11) and (x + 4)

Answer is C. (x -11)

Tamiku [17]3 years ago
5 0
X-11
because 
(x-11)(x+4)
when you multiply that you get x^2 - 7x -44

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4 years ago
What is 1 & 5/7 times 2 & 3/4
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The solution of 1\frac{5}{7} \times 2\frac{3}{4} is \frac{33}{7} \text{ or } 4.714

<em><u>Solution:</u></em>

Given that we have to find the solution of given expression

Given expression is:

1\frac{5}{7} \times 2\frac{3}{4}

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

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1\frac{5}{7} = \frac{1 \times 7+5}{5} = \frac{12}{5}

2\frac{3}{4} = \frac{2 \times 4+3}{4}=\frac{11}{4}

Now the expression becomes,

1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4}

Solve and simplify the above expression

1\frac{5}{7} \times 2\frac{3}{4} = \frac{12}{7} \times \frac{11}{4} = \frac{33}{7}\\\\1\frac{5}{7} \times 2\frac{3}{4} = \frac{33}{7}

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