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frutty [35]
3 years ago
14

an experiment consists of flipping a fair coin 4 times. What is the probability of obtaining at least one head?

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
\mathbb P(X\ge1)=1-\mathbb P(X=0)

The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is \dfrac1{2^4}=\dfrac1{16}.

So the desired probability is

1-\dfrac1{16}=\dfrac{15}{16}
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Which of the following steps were applied to abcd to obtain abcd
bulgar [2K]

Answer:

C.

Step-by-step explanation:

Move to the right 2 units,

Move down 2 units.

7 0
3 years ago
Read 2 more answers
−20=−4x−6x Find the value of x
xeze [42]

Answer:

\huge\boxed{x=2}

Step-by-step explanation:

-20=-4x-6x\qquad|\text{combine like terms}\\\\-20=-10x\qquad|\text{divide both sides by (-10)}\\\\\dfrac{-20}{-10}=\dfrac{-10x}{-10}\\\\2=x\to x=2

4 0
2 years ago
Can someone pls help with this question
vlabodo [156]

Answer:

Rise=2 Run=1 type of slope is positive slope is 2 y int is 1 and the equation is y=2x+1

Step-by-step explanation:

1. First you need slope, slope is y1-x1/x2-y2 so then you get 4/2 which is 2, we also know rise/run so rise is 2

2. 2/1 so run is 1

3. its positive since slope is positve

4.  y int is when x is 0 and y has value so y int is 1

5.  y=2x+1 since slope and y int  

:D

8 0
2 years ago
Determine two pairs of polar coordinates for the point (4, -4) with 0° ≤ θ < 360°.
umka2103 [35]
A polar coordinate is that which can be written as (r, θ) where r is the radius and θ is the angle. 

The radius, r, is also the hypotenuse of the right triangle that can be formed. Hence, it can be calculated through the equation,
    
                   r² = x² + y²
If we are to simplify this for the r alone, we have,
                     r = sqrt (x² + y²)

Substituting the known values,
               r = sqrt ((4)² + (-4)²) = 4√2

The x and y can be related through the trigonometric function, tangent. 
      tan θ = y/x
To solve for θ
   θ = tan⁻¹(y/x) = tan⁻¹(-4/4) = -45° = 315°

Hence, the polar coordinate is <em>(4√2, 315°)</em>
5 0
3 years ago
Click photo for question and options !!!!!
dezoksy [38]
\sqrt[5]{x} =  x^{\frac{1}{5}}\\&#10;\\&#10; \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} * \sqrt[5]{x} =\\&#10;x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}*x^{\frac{1}{5}}=\\&#10;x^{\frac{4}{5}}

so it is the last option
8 0
3 years ago
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