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frutty [35]
3 years ago
14

an experiment consists of flipping a fair coin 4 times. What is the probability of obtaining at least one head?

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
\mathbb P(X\ge1)=1-\mathbb P(X=0)

The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is \dfrac1{2^4}=\dfrac1{16}.

So the desired probability is

1-\dfrac1{16}=\dfrac{15}{16}
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I need help please !!!
dolphi86 [110]

Answer:

(0, 32)

Step-by-step explanation:

The function hits the vertical line (y-axis) at it's 32 mark, and 0 is always the first coordinate of a y-intercept, so it's (0, 32).

8 0
3 years ago
Ken spent 1/5 of his allowance on a movie, 3/8 on snacks, and 2/7 on games. If his allowance was $20, how much did Ken have left
Wewaii [24]
1/5 of 20 is $4. So, 20-4=$16 remaining.
3/8 of 16 is $7.50. So, 16-7.50= $8.50 remaining.
2/7 of 8.5 is $2.43. So, 8.50-2.43 is $6.07

Answer: Ken has $6.07 left after all his purchases.

6 0
3 years ago
Read 2 more answers
two similar cylinders have surface areas of 40pi square feet and 90pi. What is the ratio of the height of the large cylinders to
Sedbober [7]
The ratio of heights  = ratio of the square roots of the areas because area is 2 dimensional and height is one dimensional.

so required ratio is  sqrt 40pi :   =  sqrt40:sqrt80 =  sqrt1: sqrt2 = sqrt (1/2) = 0.7071  to 4 significant figures 
7 0
4 years ago
J(1)²,
Natali [406]

The table when completed looks like this:

x   -2   -1   0   1   2

f(x) 4   2   1    2   4.

We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).

<h3>What is a function?</h3>

A function exists as a relation between a dependent variable (f(x)) and an expression of an independent variable (x), utilized to define the value of a dependent variable from a provided value of an independent variable.

We have been given a function,

$f(x)=\left \{ {{(1/2)^{x},x\leq 0 } \atop {2^x > 0}} \right.

We have to estimate the value of f(x) when x = {-2, -1, 0, 1, 2}

If the values of x ≤ 0, take f(x) = (1/2)ˣ then

f(-2) = (1/2)⁻² = 2² = 4

f(-1) = (1/2)⁻¹ = 2¹ = 2

f(0) = (1/2)⁰ = 1

If the values of x > 0,  take f(x) = 2ˣ then

f(1) = 2¹ = 2

f(2) = 2² = 4

The table exists as follows

x   -2   -1   0   1   2

f(x) 4   2   1    2   4.

We plot these points on the graph: (-2, 4), (-1, 2), (0, 1), (1, 2), (2, 4).

To learn more about independent and dependent variable refer to:

brainly.com/question/11719274

#SPJ9

7 0
1 year ago
Read 2 more answers
Andrew withdrew $332.55 from his savings account. He now has at most $529.71. How Much cash did he originally have?
Art [367]
Andrew originally had $197.16
7 0
3 years ago
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