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LenaWriter [7]
3 years ago
6

Simplify (g^{2}h)^{4}

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

g^(8)h is may be answer as ithink

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Please help, if you need more info to answer the question please lmk
katrin2010 [14]
I believe this is right but I’m not 100%

7 0
3 years ago
Solve the system of linear equations Y+2.3=0.45x -2y=4.2-7.8
Zina [86]
Solve the following system using substitution:
{y + 2.3 = 0.45 x
{-2 y = -3.6

In the second equation, look to solve for y:
{y + 2.3 = 0.45 x
{-2 y = -3.6

-3.6 = -18/5:
-2 y = -18/5

Divide both sides by -2:
{y + 2.3 = 0.45 x
{y = 9/5

Substitute y = 9/5 into the first equation:
{4.1 = 0.45 x
{y = 9/5

In the first equation, look to solve for x:
{4.1 = 0.45 x
{y = 9/5

4.1 = 41/10 and 0.45 x = (9 x)/20:
41/10 = (9 x)/20

41/10 = (9 x)/20 is equivalent to (9 x)/20 = 41/10:
{(9 x)/20 = 41/10
{y = 9/5
Multiply both sides by 20/9:
Answer:  {x = 82/9
                {y = 9/5
3 0
3 years ago
Read 2 more answers
Please help me with these two problems I need help
sweet [91]

Answer:

24 area

18.80983669  perimeter

Step-by-step explanation:

1  (6*3/2)*2(1*3/2)+(4*3)

2 trust me

7 0
3 years ago
due 7:59 am est. Faith is saving up to buy a new bicycle. She already has $40 and can save an additional $6 per week using money
expeople1 [14]

Answer:

After 8 weeks, Faith would have $88. money saved = 40+6w

7 0
3 years ago
Read 2 more answers
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle
taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

Area  \  \   \alpha \ \  r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\  \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\  \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\


7 0
3 years ago
Read 2 more answers
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