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drek231 [11]
3 years ago
11

A skier is trying to decide whether or not to buy a season ski pass. a daily pass is $75. A season ski pass is $350. The skier w

ould have to rent skis with either pass for $30 per day. HOw many days would the skier have to go skiing in order to make the season pass less expensive than the daily pass?
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0
Since the skier has to rent skis for 30 dollars per day with both passes, we can ignore it while solving the question.

A season pass is 350, while a daily pass is 75.

\frac{350}{75} = \frac{25\times 14}{25\times 3} = \frac{14}{3} = 4 \frac{2}{3}

So a seasonal pass is equivalent to having 4.6667 daily passes. And you can't buy 0.6667 of a pass.

So, if you went at least 5 days with a seasonal pass, then the seasonal pass would be less expensive than a daily pass.
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Step-by-step explanation:

I chose to find the y-intercept since it is easy to find with the given information.

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To find the y-intercept, we must plug in the info we have and solve for b:

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3 years ago
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Varvara68 [4.7K]
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