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EleoNora [17]
3 years ago
12

The weight of 6 eggs is shown. Identify the constant of proportionality of total weight to number of

Mathematics
2 answers:
Georgia [21]3 years ago
5 0

Answer:

  • 41 g per egg

Step-by-step explanation:

<u>Proportional relationship:</u>

  • y = kx

<u>Given:</u>

  • x = 6,
  • y = 246

<u>Find k:</u>

  • 246 = 6k
  • k = 246/6
  • k = 41

Andrew [12]3 years ago
4 0
  • Constant of proportionality be k

Weight of 6eggs is 246g

Hence

\\ \sf\longmapsto a=bk

\\ \sf\longmapsto 246=6k

\\ \sf\longmapsto k=246/6

\\ \sf\longmapsto k=41

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The constant rate of proportionality is 12!
4 0
3 years ago
PLEASE HELP 50 POINTS!!!!
Mars2501 [29]

Answer:

A. 806.5 in²

Step-by-step explanation:

The figure given is a combination of a rectangle, a trapezoid and a triangle.

The formulas for the areas of each figure:

Rectangle: length x width

Trapezoid: h(\frac{b_{1}+b_{2}}{2}), where b_{1} and b_{2} are the lengths of each base and h is the height of the figure

Triangle: 1/2 bh, b = base and h = height

For each of the figures given:

rectangle: 16 x 9 = 144 in²

trapezoid: 15(\frac{31+16}{2}) = 352.5 in²

triangle: 1/2(31*20) = 310 in²

310 + 144 + 352.5 = 806.5 in²

5 0
4 years ago
Read 2 more answers
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
The admission fee to a state fair is $8.00. Each ride costs an additional $4.00. Karen only has $30.00.Which inequality could be
horsena [70]

Answer: 8 + 4x ≤ 30

Step-by-step explanation:

Since it costs $8 for Karen to enter the state fair and $4 each ride she goes, you would add 8 and 4x and include the less than or equal to sign symbol because Karen only has $30 and she got not spend anymore than $30.

5 0
4 years ago
7x + 4 = 25, then x is equal to <br><br> a) 29/ 7 b) 100/7 c) 2 d/ 3
zvonat [6]

Answer:

d) 3

Step-by-step explanation:

7x+4=25

7x=21

X=3

3 0
3 years ago
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