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levacccp [35]
3 years ago
13

How do you know where to place a decimal in a quotient?

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0
Divide. Place decimal point in the quotient. It should be placed directly above the decimal point in the dividend.
You might be interested in
How do you solve 24=x•30
ollegr [7]
I Tired To Explain It As Best As I Could.

Isolate the variable by dividing each side by factors that don’t contain the variable.

24 = x • 30

Use The Commutative Property To Reorder The Terms

24 = 30x

Swap The Sides Of The Equations

30x = 24

Divide Both Sides Of The Equations By 30

30x ÷ 30 = 24 ÷ 30

Any Expression Divided By Itself Equals 1

x= 24 ÷ 30 or x =24/30

Reduce The Fraction With 6

x = 4/5

Exact Form:

x = 4/5


Decimal Form:

x = 0.8
5 0
3 years ago
Use the distributive property to write an equivalent expression in simplest form.<br> 9(4h+ 9m)
sammy [17]

Answer:

36h+81m

Step-by-step explanation:

9*4h+9*9m=36h+81m

4 0
3 years ago
Read 2 more answers
Please Help I don't understand at all !!!!!!! I'll give 50 brainly points
kherson [118]

Answer:

0 People initially had the cold.

6 People will have it after 2 days.

Step-by-step explanation:

To find out how many people had it initially, plug 0 in for x (implying 0 days later.)

C= 1*3(0)

C= 1*0

C=0

Nobody had the cold initially.

To find out how many people had it after 2 days, plug 2 in for x. (implying 2 days later.)

C= 1*3(2)

C= 1*6

C=6

Therefore 6 people had the cold after 2 days.

I hope this helps!

4 0
3 years ago
you are building a sand castle and want to use a cylindrical bucket that holds 885 cubic inches of sand. if the bucket has a hei
natulia [17]
885/11.7=75.64/3.14=24.09=square root of 24.09=4.9
4 0
3 years ago
(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selecti
guajiro [1.7K]

Answer:

A) I) 49 teams

II)63 teams

B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

= 21+28

= 49 teams

a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

Girls remaining to choose from 7

Boys remaining to choose from 6

= 1 +7C5 + 6C5

= 1+21+6

= 28 teams

5 0
3 years ago
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