<h2>
Answer with explanation:</h2>
We are asked to prove by the method of mathematical induction that:

where n is a positive integer.
then we have:

Hence, the result is true for n=1.
- Let us assume that the result is true for n=k
i.e.

- Now, we have to prove the result for n=k+1
i.e.
<u>To prove:</u> 
Let us take n=k+1
Hence, we have:

( Since, the result was true for n=k )
Hence, we have:

Also, we know that:

(
Since, for n=k+1 being a positive integer we have:
)
Hence, we have finally,

Hence, the result holds true for n=k+1
Hence, we may infer that the result is true for all n belonging to positive integer.
i.e.
where n is a positive integer.
Answer: 8
Step-by-step explanation:
Let the number be represented by x.
Two less than three times a number is the same as six more than twice the number. This will be:
(3 × x) - 2 = (2 × x) + 6
3x - 2 = 2x + 6
Collect like terms.
3x - 2x = 6 + 2
x = 8.
The number is 8
A I guess (finger crossed )