22,222.
This is because it adds a 2 every term.
Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Answer: i think A. C. E.
Step-by-step explanation:
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so
- The length of the fencing is 80 meters, so
Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:
Then substitute for y in the first:
b) To maximize A, find the zero of the first derivative:
So y = (80-40)/2 = 20 meters.
Zeroes of a function are the values of x when f(x) = 0
So to find the zeroes of the function from the graph search for the points whose y-coordinates = 0
The y-coordinates of the point = 0, if the points lie on the x-axis
That means the zeroes of the function are the points of intersection between the graph and the x-axis
let us see that in the graph
I will draw it and post it here
From the graph
The graph intersects x-axis at points (-7, 0) and (-2, 0)
Then the zeroes of the function are (-7, 0) and (-2, 0)
Let us make the table
x f(x)
-2 0
-1 6
0 14
1 24
2 36