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3 years ago

What is the equation of a horizontal line that has a y-intercept of 3? a. b. c. d. -1/6

1 answer:

4 0

Y = 3...I believe in standard form, this would be written as : y = 0x + 3

y = an integer is a horizontal line...and if u have x = an integer, it would be a vertical line

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Why is -csc^2 (pi/4) = -2 ?

sweet-ann [11.9K]

Sin(pi/4) = 1/sqrt(2)
csc(pi/4) = sqrt(2)
csc^2(pi/4) = 2
-csc^2(pi/4) = -2

8 0

3 years ago

What is 12x + 6y = 24 for ?

EastWind [94]

It is fore multiple things. if thats your quiestion. y can =4 and x=0, or x can = 2 and y=0.

6 0

3 years ago

Read 2 more answers

28 lunch; 15 % tip<br><br><br> I need to show my workkkk

NeX [460]

28 x .15 = 4.2

28 + 4.2 = 32.2 <---- ANSWER

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Which are vertical angles to 4?

Nikolay [14]

Answer: Angle 1 only

Vertical angles are angles formed when we cross two lines like this. They are opposite one another. The other pair of vertical angles are angle 2 and angle 3.

8 0

2 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

3 years ago