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motikmotik
2 years ago
8

The probability for event A is 0.3, the probability for event B is 0.6, and the probability of events A or B is 0.8.

Mathematics
2 answers:
kogti [31]2 years ago
4 0

Answer:

C

Step-by-step explanation:

Nitella [24]2 years ago
3 0

The events are not mutually exclusive because D. The sum of P(A) and P(B) is not equal to P(A or B).

Given that

  • probability for event A, P(A) = 0.3.
  • probability for event B, P(B) = 0.6.
  • the probability of events A or B, P(A or B) = 0.8.

For mutually exclusive events, P(A) + P(B) = P(A or B).

So, P(A) + P(B) = 0.3 + 0.6 = 0.9

P(A or B) = 0.8

Since P(A) + P(B) = 0.9 ≠ P(A or B) = 0.8

The events are not mutually exclusive.

So, the events are not mutually exclusive because D. The sum of P(A) and P(B) is not equal to P(A or B).

Learn more about mutually exclusive events here:

brainly.com/question/14660720

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Answer:

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Step-by-step explanation:

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The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

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I hope this helps!  

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Step-by-step explanation:

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Step-by-step explanation:

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