Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer:
1 
Step-by-step explanation:
5/3 = 3/3 * 2/3
3/3 = 1
So the answer is 1 
Answer:
Approximately 0.333
Step-by-step explanation:
If we graph this we see that the line goes over the y-axis at (0,0.333)
*I use desmos graphing calculator*