<img src="https://tex.z-dn.net/?f=%5Csf%20-9%288-2h%29" id="TexFormula1" title="\sf -9(8-2h)" alt="\sf -9(8-2h)" align="absmiddl

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Veronika [31]

2 years ago

e" class="latex-formula">

Mathematics

2 answers:

grigory [225]2 years ago

4 0

Answer:

$-72+18h$

Step-by-step explanation:

$-9(8-2h)$

$\mathrm{Multiply}-9\:\mathrm{to\:the\:values\:in\:the\:parenthesis}$

$-9(8-2h)$

$-9\cdot8=-72$

$-9\cdot-2=18$

$=-72+18h$

coldgirl [10]2 years ago

3 0

Answer:

$- 9(8 - 2h) \\ by \: distributive \: property \\ = - 9 \times 8 - ( - 9) \times ( - 2h) \\ = - 72 - 18h$

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Ymorist [56]

Answer:

$t=\frac{78-75}{\frac{7}{\sqrt{20}}}=1.917$

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$p_v =2*P(t_{19}>1.917)=0.0704$

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a. No

Step-by-step explanation:

Information given

$\bar X=78$ represent the sample mean

$s=7$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =75$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to check if the true mean is different from 75, the system of hypothesis would be:

Null hypothesis: $\mu =75$

Alternative hypothesis: $\mu \neq 75$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{78-75}{\frac{7}{\sqrt{20}}}=1.917$

The degrees of freedom are given by:

$df= n-1 = 20-1=19$

The p value would be given by:

$p_v =2*P(t_{19}>1.917)=0.0704$

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