What is the equation of a line with slope -1/2 passing through (-5,4)?

1 answer:

4 0

For this question you need to use what's called point-slope form. It's named this way because you can use it if you have both the slope and a point at which the line passes through. That said, the equation is as follows:

y - y1 = m(x - x1)

Both y1 and x1 represent the y and x coordinates you are given in the question. Also, m represents the slope of the line that you are given. Knowing this, our equation now looks like this:

y - 4 = -0.5(x - (-5))

And now simplify:

y - 4 = -0.5(x + 5)
y - 4 = -0.5x - 2.5

y = -0.5x + 1.5

You might be interested in

Solve the right triangle.<br> Round your answers to the nearest tenth.

kondor19780726 [428]

Sorry, I think you forgot the photo of the problem

5 0

3 years ago

New flowers are being planted in a circular bed with a 14 foot diameter. If each flower requires 1 square foot of space, how man

alexgriva [62]

You can fit 153 flowers in a circle with the diameter of 14. You find the area of the circle by doing pi times 7 squared.

7 0

3 years ago

What is the distance between -45 and 65

tatyana61 [14]

Answer:

110

Step-by-step explanation:

What is the Difference between -45 and +65? In other words, what is the Difference between negative 45 and positive 65?

To solve this math problem, start by picturing a horizontal number line that starts with negative infinity on the left and ends with positive infinity on the right:

∞ ..... -3, -2, -1, 0, +1, +2, +3, .... ∞

The Difference between -45 and +65 is the distance between -45 and +65 on our number line above. Thus, the Difference between two numbers will always be a positive number.

It is a two-step process to calculate the Difference between -45 and +65. Step 1 is to subtract +65 from -45, and Step 2 is to find the absolute value of the Step 1 answer. Here is the math to illustrate better:

(-45) - (+65) = -110

|-110| = 110

That's it! The Difference between -45 and +65 is as follows:

110

5 0

3 years ago

Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul

irina1246 [14]

Answer:

As shown below

Step-by-step explanation:

Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:

$F(x) = 0, 0$