$\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}$

7 0

3 years ago

Every / represents a fraction

enyata [817]

Answer:

410.305

Step-by-step explanation:

I forgot how to do standard sorry..

3 0

3 years ago

X+2y=8 x-2y=-4 solve by system of equations

Vsevolod [243]

Answer:

Step-by-step explanation:

x + 2y = 8 -----------(I)

x - 2y = -4 -----------(II)

Add equation (I) & (II) and thus y will be eliminated and we can get the value of 'x'

(I) x + 2y = 8

(II) <u>x - 2y = -4</u><u> </u>{Now add}

2x = 4

x = 4/2

x = 2

Substitute x = 2 in equation (I)

2 + 2y = 8

2y = 8 - 2

2y = 6

y = 6/2

y = 3

3 0

3 years ago