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2 years ago

Does a perpendicular bisector have to be a line?

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

5 0

Answer:yes

Step-by-step explanation:

it is a line or segment

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garri49 [273]

Glass and Titanium. Glass is because (10,40) (y over x) is 4 and Titanium is because (10,60) is 6 cork and lead are not since when dividing y over x it doesn't equal 2.

5 0

4 years ago

Can someone helllllppp me on 5 more problems like this n I’ll give u 20 dollars in cashapp plzzz I’m being serious

Vlada [557]

Answer:

y = x - 5

Step-by-step explanation:

$\rm Solve \: for \: y: \\ \rm \longrightarrow x - y= 5 \\ \\ \rm Subtract \: x \: from \: both \: sides: \\ \rm \longrightarrow x - y - x = 5 - x \\ \\ \rm \longrightarrow -y = 5 - x \\ \\ \rm Multiply \: both \: sides \: by \: -1: \\ \rm \longrightarrow - y \times ( - 1) = (5 - x) \times ( - 1) \\ \\ \rm \longrightarrow y = x - 5$

5 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

Least common denumertor of 11/3 9/10

Alisiya [41]

30 since that’s the lowest number both 3 and 10 can fit in

8 0

3 years ago

In a fruit basket containing apples and oranges,1/4 of the fruit are oranges.

Oxana [17]

None of these answers can be the answer okay so it should be 1/6
Therefore the answer is a.
To get this first you add 3+15=18
Next you divide it by 6, 18 divided by 6 =3
Therefore 1/6=3
I hope that this helped

6 0

3 years ago