We have that
<span>points A (-5, 6) and B (7, -1)
Part A)
find the distance
d=</span>√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193 units
Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5
the midpoint is (1,2.5)
Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12
the slope m=-7/12
No because the 3 is the tens place. So its supposed to 3 ten blocks
1 x 5 = 5 + 3 = 8
tell me if it’s not the answer your looking for
If C= (-10, -9, -8, -7 ,-6 , -5) and D= ( -6, -5, -4, -3, -2, -1, ) , what is C n D ?
andrey2020 [161]
Answer:
C ∩ D = -5, -6
Step-by-step explanation:
Commons ones in both C and D are -5 and -6