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qwelly [4]
2 years ago
5

A rectangle has a length of 4 mm has an area is 44 mm² width of the rectangle is

Mathematics
2 answers:
nordsb [41]2 years ago
5 0
The answer is : w=1.1×10^7mm
SVEN [57.7K]2 years ago
3 0

Answer:

11

Step-by-step explanation:

The formula for area is l * w = a (length * width = area)

4 is our length, and 44 is the area, so the equation turns to this:

4 * x = 44

To solve for x, just divide 44 by 4.

44 / 4 = 11.

Now we enter that into our equation so it looks like this:

4 mm * 11 mm = 44 mm^2.

Hope this helped :)

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Maddie and her friends are making s'mores over the campfire. they have a bag of 48 marshmallows, 2 packs of graham crackers cont
VladimirAG [237]

The answer would be 16 S'mores and the limiting reactant would be the grahams.


(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)


Limiting reactant would be the reactant that runs out first.


Let's take your problem into account and see what we have:

48 marshallows

32 grahams (2 x 16 per pack)

45 chocolate pieces (5 x 15 pieces per bar)


Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.

The maximum yield of marshmallows is 48.

The maximum yield of chocolate is 45.


Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.

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3 years ago
a rule that assigns each value of the independent variable to exactly one value of the dependent variable?
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You roll a six-sided die. Find the probability of each event.
kirill [66]

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5 0
3 years ago
Find the circumference of a circle whose area is 24
zalisa [80]

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________


The area, "A", of a circle:

A = \pi * r² ;

Note: \pi  = 3.14 .

The area of the circumference, "C", of a circle:

C = 2 \pi r .

__________________________________________

Given:

A = 24 ;

Use the formula for the area, "A" of a circle, to find the radius, "r" .

Then, plug the value obtained for "r" into the formula for the circumference, "C" , of a circle:

C = 2\pi r l

To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

24 = 3.14 * r² ;

↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

to isolate "r" on one side of the equation; & to solve for the radius, "r" ;

→ ⁺√(r²) = ⁺√(7.64331210191) ;

to get:

→ r = 2.76281034802 ;

____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

→ C = 2 \pi * r ;

to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________

6 0
3 years ago
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