<span>-2x^2 + 10x + 9 =0
multiply whole equation by -1
2x^2 -10x -9 =0
(sqrt2x)^2 -2(sqrt2x)(5/</span>sqrt2) -9=0
add (5/sqrt2)^2 on both sides
(sqrt2x)^2 -2(sqrt2x)(5/sqrt2) + (5/sqrt2)^2-9=(5/sqrt2)^2
a^2-2ab+b^2=(a-b)^2
(sqrt2x - 5/sqrt2)^2=(5/sqrt2)^2+9
(sqrt2x - 5/sqrt2)^2=21.5
taking squareroot on both sides
sqrt2x - 5/sqrt2 = +-4.64
so
sqrt2x - 5/sqrt2 = +4.64 or sqrt2x - 5/sqrt2 = -4.64
sqrt2x = 4.64 + 5/sqrt2 sqrt2x = -4.64 + 5/sqrt2
sqrt2x =8.18 sqrt2x = -1.1045
x=8.18/sqrt2 x= -1.1045/sqrt2
x=5.78 x=-0.781
For figure one angle 1 is 98 and for angle 2 it is 82 THEN for figure two both angles are 64 THE LAST ONE figure 3 angle 1 is 157 and angle 2 is 23
Answer:
A = 105 cm²
Step-by-step explanation:
The area (A) of the trapezoid is calculated as
A = 
[ (b₁ + b₂)h ]
where h is the height and b₁, b₂ the parallel bases
Here h = 5 , b₁ = 24 and b₂ = 18 , then
A = [ (24 + 18)5 ]
= (42 × 5)
= × 210
= 105 cm²
