2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j
Answer <em>X ≥ 10</em>
<em></em>
Step 1- Multiply Both Sides of the inequality by 2! :) = 10+x≥20
Step 2- Move the constant to the right-hand side and change it's side! :)
= x≥20-10
Step 3- Subtrcact the numbers! :) =x≥10
And Final Answer isssss....<em> X ≥ 10! </em>
Hope this helps! Have a great day or night!
Answer:
So total cost of tickets = $64
Step-by-step explanation:
Given:
Cost of adult = $12
Cost of Children = $7
Total Adults = 3
Total children = 4
To Find:
Total Cost = ?
Solution:
We are given per person price and no of persons too now
Total cost = Cost of children ticket + Cost of Adults ticket
Now we will find the values
Cost of 3 adults ticket = total person * cost per person
= 3 * 12
=$36
Cost of 4 Children ticket = total person * cost per person
= 4 * 7
=$28
Now
Total cost = Cost of children ticket + Cost of Adults ticket
putting value
Total cost = 28 + 36
= $ 64
So total cost of tickets = $64
Answer:
The expression to the statement in roaster form is:
{1,2,3,4,5,6}
Step-by-step explanation:
<em>" To express the set in roster form the elements of a set are listed within the curly brackets and are separated by commas " .</em>
We are given a statement as:
" The set of natural numbers less than 7" is represented in roaster form as:
{1,2,3,4,5,6}
( since, the natural numbers are the positive integers (whole numbers) 1, 2, 3, etc. and we asked to find the numbers less than 7).
The area is 28.26
to find the radius you have to divide the diameter by 2 which you’ll get 3
then plug it into the equation
A=3.14•3^2
