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Wittaler [7]
2 years ago
12

An athlete has run 200m in a 1.5km race. What fraction is she through the race

Mathematics
1 answer:
SashulF [63]2 years ago
5 0

Answer:

2/15

Step-by-step explanation:

So 1 km is 1000m

Meaning the race is 1500m

200m out of 1500m = \frac{200}{1500}

Simplified down to 2/15

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A person walks 2 3 of a mile in 2 9 of a hour. Which complex fraction when simplified will compute the unit rate of miles per ho
GaryK [48]
2/3  /  2/9
= 2/3 * 9/2
=18/6
=3

rate = 3 miles per hour
3 0
3 years ago
Read 2 more answers
Solve:
mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

1.

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2.

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

3.

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0
3 years ago
How to do this I don’t understand this please help
VashaNatasha [74]
I'm guessing you'd combine them. And the end equation would be

81x6y
7 0
3 years ago
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
swat32

Answer:

Test statistic, t_{s} = -0.603 (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

\bar{d} = \frac{\sum x-y}{n}

\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625

Standard deviation: SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1}  }

\sum d^{2}  = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2}  = 63

SD = \sqrt{\frac{63 - 8 *  (-0.625)^2}{8-1}  }

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n}  } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8}  }

t_{s} = -0.6033

6 0
3 years ago
What is the value of B?
iragen [17]

2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)

\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT

<h3>Answer: B = 2</h3>
8 0
3 years ago
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