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2 years ago

An athlete has run 200m in a 1.5km race. What fraction is she through the race

Mathematics

1 answer:

SashulF [63]2 years ago

5 0

Answer:

2/15

Step-by-step explanation:

So 1 km is 1000m

Meaning the race is 1500m

200m out of 1500m = $\frac{200}{1500}$

Simplified down to 2/15

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A person walks 2 3 of a mile in 2 9 of a hour. Which complex fraction when simplified will compute the unit rate of miles per ho

GaryK [48]

2/3 / 2/9
= 2/3 * 9/2
=18/6
=3

rate = 3 miles per hour

3 0

3 years ago

Read 2 more answers

Solve:

mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0

3 years ago

How to do this I don’t understand this please help

VashaNatasha [74]

I'm guessing you'd combine them. And the end equation would be

81x6y

7 0

3 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

3 years ago

What is the value of B?

iragen [17]

$2x^2-12xy-32y^2=2(x-8y)(x+By)\qquad|\text{use distributive property}\\\\2x^2-12xy-32y^2=(2x-16y)(x+By)\\\\2x^2-12xy-32y^2=(2x)(x)+(2x)(By)+(-16y)(x)+(-16y)(By)\\\\2x^2-12xy-32y^2=2x^2+2Bxy-16xy-16By^2\\\\2x^2-12xy-32y^2=2x^2+(2B-16)xy+(-16By)$

$\text{therefore:}\\\\2B-16=-12\ \text{and}\ -16B=-32\\\\2B=4\ \text{and}\ B=2\\\\B=2\ \text{and}\ B=2\qquadCORRECT$

<h3>Answer: B = 2</h3>

8 0

3 years ago