Answer:
4x=90
X=90÷4
X=22.5
5x-27=90
5x=90+27
5x=117
X=117÷5
X=23.4
So 23.4 is a larger angle
The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.
Ideal gas behavior:
Suppose the initial volume of carbon dioxide gas is V = 3.5l
Initial pressure is P = 125 kPa
Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L
The final pressure of the gas is P'.
We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.
PV = P'V'
125 × 3.5 = P'× 2
P'= 218.75 kPa
Therefore, the final pressure is 218.5 kPa.
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(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
